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A Zener diode is specified having a brea...

A Zener diode is specified having a breakdown voltage of 9.1 V with a maximum power dissipation of 364 mW. What is the maximum current that the diode can handle.

A

40 mA

B

60 mA

C

50 mA

D

45 mA

Text Solution

Verified by Experts

The correct Answer is:
A
The maximum permissible current is
`I_(Z_("max"))=P/V_z=(364xx10^(-3))/9.1=40 mA`
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