If `alpha and beta` are the current gain in the CB and CE configurations respectively of the transistor circuit, then `(beta-alpha)/(alphabeta)=`

Options

A. zero
B. 1
C. 2
D. 5

Answer

B

Explanation

Since `beta=alpha/(1-alpha)`...(i)
`therefore alphabeta=alpha^2/(1-alpha)-alpha"or" beta-alpha=alpha^2/(1-alpha)`..(ii)
`therefore (beta-alpha)/(alphabeta)=(alpha^2/(1-alpha))((1-alpha)/alpha^2)=1`