A transistor has a current amplification factor (current gain) of 50. In a common emitter amplifier circuit, the collector resistance is chosen as `5Omega` and the input resistance is `1Omega`. The output voltage if input voltage is 0.01 V is

Options

A. -2 V
B. `-5 V`
C. -2.5 V
D. -1 V

Answer

C

Explanation

The voltage gain of a common emitter amplifier
`A_v=-(betaR_o)/R_i " " or " " V_o/v_i= - (betaR_C)/(R_B)`
Output voltage,
`therefore V_o=-(betaR_CV_i)/(R_B)=-(50xx5xx0.01)/1=-2.5 V`