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In a transistor connected in a common em...

In a transistor connected in a common emitter mode `R_C = 4kOmega, R_1 = 1kOmega, I_C = 1mA` and `I_B = 20 muA`. Find the voltage gain.

A

100

B

200

C

300

D

400

Text Solution

Verified by Experts

The correct Answer is:
B
Voltage gain, `A_V=(betaR_C)/R_I=I_C/I_BxxR_C/R_I`
`=(1xx10^(-3)xx4xx10^3)/(20xx10^(-6)xx1xx10^3)=200`
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