If a change of `100 mu A` in the base current of an `n-p-n` transistor in `CE` causes a change of `10 mA` in the collector current, the `ac` current gain of the transistor is

Options

A. 50
B. 100
C. 200
D. 150

Answer

B

Explanation

Here, `DeltaI_B=100 mu A = 100 xx 10^(-6) A`
`DeltaI_C=10 mA = 10 xx 10^(-3)A`
`therefore` ac current gain , `beta_(ac)=(DeltaI_C)/(DeltaI_B)=(10xx10^(-3))/(100xx10^(-6))=100`