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In the circuit shown in figure, when the...

In the circuit shown in figure, when the input voltage of the base resistance is 10 V, `V_(be)` is zero and `V_(ce)` is also zero. Then

A

`beta=110`

B

`I_b=25 muA`

C

`I_c=3.33 mA`

D

both (A) and (C )

Text Solution

Verified by Experts

The correct Answer is:
D
Given `V_i`=10 V, `R_b=400 kOmega=400xx10^3 Omega`
`R_c=3 kOmega=3xx10^3 Omega, V_(be)=0,V_(ce)=0,V_("CC")=10 V`
As `V_i-V_(be)=R_b I_b`
`therefore 10-0=(400xx10^3)I_b`
`l_b=10/(400xx10^3)`
`=25xx10^(-6) A = 25 muA`
`V_("CC")=V_(ce)=I_c R_c`
`I_c=10/(3xx10^3)=3.33xx10^(-3)=3.33 mA`
`beta=I_c/I_b=(3.33xx10^(-3))/(25xx10^(-6))=133`
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