Home
Class 12
PHYSICS
In the circuit shown in figure, if the A...

In the circuit shown in figure, if the A diode forward voltage drop is 0.3 V, the voltage difference between A and B is

A

1.3 V

B

2.3 V

C

0

D

0.5 V

Text Solution

Verified by Experts

The correct Answer is:
B

Let V be the potential difference between A and B, then
`V-0.3=(5+5)xx10^3xx(0.2xx10^(-3))=2`
or `V=2+0.3 = 2.3 V`
Promotional Banner

Topper's Solved these Questions

  • SEMICONDUCTOR ELECTRONICS : MATERIALS , DEVICES AND SIMPLE CIRCUITS

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos
  • SEMICONDUCTOR ELECTRONICS : MATERIALS , DEVICES AND SIMPLE CIRCUITS

    NCERT FINGERTIPS|Exercise Higher Order Thinking Skills|8 Videos
  • RAY OPTICS AND OPTICAL INSTRUMENTS

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos
  • WAVE OPTICS

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

In the circuit shown in figure, if the diode forward voltage drop is 0.3 V, then the voltage difference between A to B is,

In the circuit shown(Fig.) if the diode forward voltage drop is 0.3 V , the voltage difference between A and B is : .

In the circuit shown in figure, Voltage V_0 is–

In the circuit shown in figure, Voltage V_(0) is

In the circuit shown infigure, voltage V_(0) is,

For the circuit shown in figure, determine the unknown voltage drop V_(1) .

For the circuit shown in figure , determine the unknown voltage drop V_(1) .

In the circuit shown in figure the maximum output voltage V_(0) is

In the circuit shown in figure, the final voltage drop across the capacitor C is :

In the circuit shown in figure the voltage in L and in C are .