Two resistance `R_(1)` and `R_(2)` are joined as shown in figure to two batteries of emf `E_(1)` and `E_(2)`. If `E_(2)` is short circuited, what is the current through `R_(1)` ?

Two cells of emf E_(1) and E_(2) are connected to two resistors R_(1) and R_(2) as shown. If E_(2) is short circuited then current through R_(1) and R_(2) are

If the resistances are chosen for the circuit shown in figure in such a way that no current flows through the battery with emf E_(1) , the voltage V_(2) across R_(2) and the current I_(3) flowing through R_(3) are respectively,

The cells of emf's E_(1) and E_(2) be connector in parallel in a circuit. Let r_(1) and r_(2) be the internal resistance of the cells. Then the current through the circuit is

Two cells of emf E_(1) and E_(2) are joined in opposition ( such that E_(1) gt E_(2) ). If r_(1) and r_(2) be the internal resistance and R be the external resistance , then the terminal potential difference is

Two cells of emf E_(1) and E_(2) are joined in opposition (such that E_(1) gt E_(2) ) . If r_(1) be the internal resistances and R be the external resistance, then the terminal potential difference is

In the circuit shown in fig E_1 = 3 volts, E_2 = 2volts, E_3 = 1volt and R = r_1 = r_2= r_3= 1 ohm. (i) Find the potential difference between the points A and B and the currents through each branch. (ii) If r_2 is short circuited and the point A is connected to point B, find the current through E_1, E_2, E_3 and the resistor R.

In the circuit in figure E_1=3V, E_2=2V, E_3=1V and R=r_1-r_2-r_3=1Omega a. Find the potential differece between the points A and B and the currents through each branch. b. If r_2 is short circuited and the point A is connected to point B , find the currents through E_1,E_2, E_3 and the resistor R

In the circuit shown in figure-3.344 if battery is ideal , then time after which current in R_(3) becomes (1/e) time that of maximum current through it is :

E_(1) and E_(2) are two batteries having emfs of 3V and 4V and internal resistances of 2Omega and 1Omega respectively. They are connected as shown in Figure 2 below. Using Kirchhoff.s Laws of electrical circuits, calculate the currents I_(1) and I_(2) .