The resistance of a coi is `4.2Omega` at `100^(@)C` and the temperature coefficient of resistance of its material is `(0.004)/(.^(@)C)`. Its resistance at `0^(@)C` is

Resistance of a coil is 4.2 Omega at 100^@C and the temperature coefficient of resistance of its material is 0.004//"^@C . Then its resistance at 0^@C is ( Omega )

Resistance or coil at 100^(@) C is 4.2 Omega . If temperature co-efficient of resistance of material is 0.004 (""^(@)C)^(-1) so what will be its resistance at 0^(@)C ?

A wire has a resistance of 2.5Omega at 100^(@)C . Temperature coefficient of resistance of the material alpha=3.6xx10^(-3)K^(-1) . Find its resistance at 0^(@)C .

The resistance of a copper wire is 20 Omega at 0^@C . Find the resistance at 60^@C if the temperature coefficient of resistance of material is 0.004//^@C .

If the resistance of a conductor is 5 Omega at 50^(@)C and 7Omega at 100^(@)C then the mean temperature coefficient of resistance of the material is

If the resistance of a conductor is 5 Omega at 50^(@)C and 7Omega at 100^(@)C then the mean temperature coefficient of resistance of the material is

A metallic wire has a resistance of 3.0 Omega at 0^@C and 4.8 Omega at 150^@C . Find the temperature coefficient of resistance of its material.

A wire has a resistance of 2.5 Omega at 100^@ C. Temperature coefficient of resistance of the material alpha = 3.6 xx 10^(-3) K^(-1) at 25^@ C. Find its resistance at 25^@ C .