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If e^(itheta)=costheta+isintheta, find ...

If `e^(itheta)=costheta+isintheta,` find the value of `|1e^(ipi//3)e^(ipi//4)e^(-ipi//3)1e^(i2pi//3)e^(-ipi//4)e^(-i2pi//3)1|`

Answer

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Knowledge Check

  • If e^(lx)=cosx+isinx and x+iy=|(1,e^(pi i//4),e^(pi i//3)),(e^(-pi i//4),1,e^(2pi i//3)),(e^(-pi i//3),e^(-2pi i//3),e^(-2pi i //3))| , then

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    `x=-1,y=sqrt(2)`
    B
    `x=1,y=-sqrt(2)`
    C
    `x=-sqrt(2),y=sqrt(2)`
    D
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  • If e^(itheta)=costheta+isintheta,A+B+C=pi and z=|(e^(2iA),e^(-iC),e^(-iB)),(e^(-iC),e^(2iB),e^(-iA)),(e^(-iB),e^(-iA),e^(2iC))| , then

    A
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    C
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  • The value of int_(pi//4)^(pi//4)(e^(x)sec^(2)x)/(e^(2x)-1)dx , is

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    B
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    C
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    D
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