A magnet of dipole moment `2Am^(2)` is deflected through `30^(@)` from magnetic meridian. The required deflecting torque is `(B_(H)=0.4xx10^(-4)T)`

A dipole of magnetic moment (2.5 Am^2) is deflected through 30° from magnetic meridian. If the earth's horizontal field is (0.4x10^-4) I calculate the deflection moment.

A bar magnet of 5 cm long having a pole strenght of 20 A.m . Is deflected through 30^(@) from the magnetic meridian. If H=(320)/(4pi)A//m , the deflecting couple is

A magnet of magnetic dipole moment 4 Am^(2) is deflected though 45^(@) from the direction of a magnetic field of induction 3sqrt(2)" Wb/m"^(2) . What is the magnitude of the torque on the magnet?

A magnet 10 cm and having a pole strength of 8 units is deflected through 45^(@) from the magnetic meridian. If the earth's magnetic field is 0.32 oersted, value of the deflecting couple in dynes cm will be

A magnet 10 cm and having a pole strength of 8 units is deflected through 45^(@) from the magnetic meridian. If the earth's magnetic field is 0.32 oersted, value of the deflecting couple in dynes cm will be

A magnet of magnetic dipole moment 2Am2 is deflected through 30^@ from the direction of a magnetic field of induction 2frac(Wb)(m^2) . Find the magnitude of the torque.

A magnetic wire of dipole moment 4pi Am^(2) is bent in the form of semicircle. The new magnetic moment is

A magnetic wire of dipole moment 4pi Am^(2) is bent in the form of semicircle. The new magnetic moment is

A magnet is suspended in the magnetic meridian with an untwisted wire. The upper end of wire is rotated through 180^(@) to deflect the magnet by 30^(@) from magnetic meridian. When this magnet is replaced by another magnet, the upper end of wire is rotated through 270^(@) to deflect the magnet 30^(@) from magnetic meridian. The ratio of magnetic moment of magnets