Find the least count of the vernier caliper as shown in figure below. The main scale is in mm (i.e., 10mm, 20mm etc.)

The least count of the vernier calipers shown in the figure is ________.

What is least count of the given vernier caliper? There is one vernier caliper in which 1 main scale division (MSD) is 1mm. It is given that 10 divisions of vernier scale match with 9 divisions of main scale. Given vernier caliper is used to measure the edge of a cube. Main scale reading (MSR) was found to be 10 and first division of the vernier scale was found to be coinciding with some division of the main scale. Mass of the cube is 2.736g.

The least count of vernier callipers is 0.1 mm . The main scale reading before the zero of the vernier scale is 10 and the zeroth division of the vernier scale coincides with the main scale division. Given that each main scale division is 1mm . The measured value should be expressed as

A vernier calipers has positive zero error of 0.05 mm. While finding the diameter a cyclinder, the MSR is 9 mm ad the VCD is 9. If the least count of the vernier calipers is 0.1 mm, the area of cross- section of the cylinder is ________ mm^(2)

Least count of a vernier caliper is (1)/(10N) cm.The value of one division on the main scale is 1mm" .Then the number of divisions of the main scale that coincide with N divisions of vernier scale is (A) 10N (B) "(N)/(10) (C) (N-1) (D) N-10

19 divisions on the main scale of a vernier calipers coincide with 20 divisions on the vernier scale. If each division on the main scale is of 1 cm , determine the least count of instrument.

If the length of a vernier scale having 25 divisions correspond to 23 main scale division and given that 1M.S.D =1 mm the least count of the vernier calipers is "______"