`K_(p)` for `3//2H_(2)+1//2N_(2) hArr NH_(3)` are `0.0266` and `0.0129 atm^(-1)`, respectively, at `350^(@)C` and `400^(@)C`. Calculate the heat of formation of `NH_(3)`.

K_(p) for the reaction N_(2)+3H_(2) hArr 2NH_(3) is 1.6xx10^(-4) atm^(-2) at 400^(@)C . What will be K_(p) at 500^(@)C ? The heat of reaction on this temperature is -25.14 kcal?

AT673 K. in the formation of NH_(3) From N_(2) and H_(2) , the partial pressures of N_(2) , H_(2) and and NH_(3) at equilibrium are 0.5 , 1 and 9 xx 10^(-3) atm respectively. (N_(2) + 3H_(2) hArr + Q) Calculate K_(c) for the reaction.

K_(p) for the reaction N_(2)+3H_(2) hArr 2NH_(3) at 400^(@)C is 1.64xx10^(-4) atm^(-2) . Find K_(c) .

For the reaction, N_(2)+3H_(2)hArr2NH_(3) , the units of K_(c) "and" K_(p) respectively are:

For the reaction, N_(2)+3H_(2)hArr2NH_(3) , the units of K_(c) "and" K_(p) respectively are:

At 450^(@)C the equilibrium constant K_(p) for the reaction N_(2)+3H_(2) hArr 2NH_(3) was found to be 1.6xx10^(-5) at a pressure of 200 atm. If N_(2) and H_(2) are taken in 1:3 ratio. What is % of NH_(3) formed at this temperature?

At 450^(@)C the equilibrium constant K_(p) for the reaction N_(2)+3H_(2) hArr 2NH_(3) was found to be 1.6xx10^(-5) at a pressure of 200 atm. If N_(2) and H_(2) are taken in 1:3 ratio. What is % of NH_(3) formed at this temperature?