At a distance r from a point located at origin in space, the electric potential varies as `V= 10r`. Find the electric field at `vecr = 3hati + 4 hatj - 5hatk`.

What will be the electric flux passing through the area vecS=10hati placed in an electric field of intensity vecE=3hati+4hatj+5hatk ?

The potential at a point in an electric field is give by V=Rr volt where r is distance of the point from the origin of the co-ordinate system. Find the electric field at a point r=(hati+2hatj+2sqrt(5)hatk)m

Let V_0 be the potential at the origin in an electric field vecE = 4hati + 5hatj . The potential at the point (x,y) is

Let V_0 be the potential at the origin in an electric field vecE = 4hati + 5hatj . The potential at the point (x,y) is

Find the distance of the point with position vector - hati - 5 hatj - 10 hatk from the point of intersection of the line vec(r) = (2 hati - hatj + 2 hatk) + lambda ( 3 hati + 4 hatj + 12 hatk) with the plane vec(r). (hati - hatj + hatk) = 5 .

The electric field and the potential of an electric dipole vary with distance r as

A positive charge 50 muC is located in xy plane at a position vector r_0 = 4hati + 4hatj . the electric field strength E at a point whose position vector is vecr = 10hati - 4hatj is ( vecr_0 and vecr are expressed in metre)