A body is projected vertically upwards. If `t_(1)` and `t_(2)` be the times at which it is at height `h` above the point of projection while ascending and descending respectively, then `h` is

A body is projected verticallt upwards. If t_(1) and t_(2) be the times at which it is at a height h above the point of projection while ascending and descending respectively, then:

A body is vertically upwards. If t_(1) and t_(2) are the times at which it is height h above the point of projection while ascending and descending, respectively, find (a) the velocity of projection and height h, (b) the maximum height reached by the body and (c ) the velocity of the body at height h//2 .

A stone projected vertically upward moves according to the law s=48t-16t^2 . The time taken by the stone to reach the point of projection is

A body is projected vertically upwards . The times corresponding to height h while ascending and while descending are t_(1)andt_(2) respectively . Then the velocity of projection is (g is acceleration due to gravity)

A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

A body is projected vertically upwards and attains maximum height H. If the time to reach height 'h' and H are in the ratio of 1:3, then the ratio h/H is :

A body is projected veritclaly upwards.The times corresponding to height h while ascending and while descending are t_(1) and t_(2) respectively. Then, the velocity of projection will be (take g as acceleration due to gravity)