When x grams of steam at `100^(@)C` is mixed with y grams of ice at `0^(@)C`, we obtain `(x + y)` grams of water at `100^(@)C`. What is the ratio `y//x` ?

When x gram of steam is mixed with y grams of ice at 0^(@)C , we obtain (x+y) grams of water at 100^(@)C . Find the value of (y)/(x)

10 grams of steam at 100^(@)C is mixed with 50 gm of ice at 0^(@)C then final temperature is

10 grams of steam at 100^(@) C is mixed with 50 gm of ice at 0^(@) C then final temperture is

10 grams of stream at 100^@ C is mixed with 50 gm of ice at 0^@ C then final temperature is

When m gram of steam at 100^(@) C is mixed with 200 gm of ice at 0^(@)C . it results in water at 40^(@) C . Find the value of m in gram . (given : Latent heat of fusion ( L_f ) = 80 cal/gm, Latent heat of vaporisation ( L_v ) = 540 cal/gm., specific heat of water ( C_w )= 1 cal/gm/C)

When m gram of steam at 100^(@) C is mixed with 200 gm of ice at 0^(@)C . it results in water at 40^(@) C . Find the value of m in gram . (given : Latent heat of fusion ( L_f ) = 80 cal/gm, Latent heat of vaporisation ( L_v ) = 540 cal/gm., specific heat of water ( C_w )= 1 cal/gm/C)

M gram of ice at 0^@ C is mixed with 3 M gram of water at 80^@ C then the final temperature is.