Balmer gave an equation for wavelength of visible radiation of H-spectrum as `lambda=(kn^(2))/(n^(2)-4)`. The value of k in terms of Rydberg's constant R is `m//R`, where m is :

Balmer gives an equation for wavelength of visible radition of H^(-) spectrum as lambda=(kn^(2))/(n^(2)-4) .The value of k in terms of Rydberg's constant R is

Balmer given an equation for wavelength of visible radiation of H-spectrum as lambda=(kn^(2))/(n^(2)-4) .The value of k in terms of Rydbrum constant R is

Balmer gave an equation for wavelength of visible region of H-spectrum as lambda=(Kn^(2))/(n^(2)-4) . Where n= principal quantum number of energy level, K=constant in terms of R (Rydberg constant). The value of K in term of R is :

Balmer gave an equation for wavelegth of visible region of H-spectrum as lambda=(Kn^(2))/(n^(2)-4). Where n= pricipal quantum number of energy level, K=constant in terms of R (Rydberg constant). The value of K in term of R is :

Balmer gave an equation for wavelegth of visible region of H-spectrum as lambda=(Kn^(2))/(n^(2)-4). Where n= pricipal quantum number of energy level, K=constant in terms of R (Rydberg constant). The value of K in term of R is :

Balmer gave an equation for wavelength of visible region of H-spectrum as barv =(n^2 - 4)/(Kn^2) where n = principal quantum number of energy level, K = constant terms.of R (Rydberg constant). The value of K in terms of R is:

The wave number of the first emission line in the Balmer series of H - Spectrum is (n)/(36)R . The value of 'n' is. (R = Rydberg constant):

The wave number of the first emission line in the Balmer series of H - Spectrum is (n)/(36)R . The value of 'n' is. (R = Rydberg constant):