By using properties of determinants. Show that: `|1+a^2-b^2 2a b-2b2a b1-a^2+b^2 2a2b-2a1-a^2-b^2|=(1+a^2+b^2)^3`

1+a^(2)-b^(2),2ab,-2b2ab,1-a^(2)+b^(2),2a2b,-2a,1-a^(2)-b^(2)]|=(1+a^(2)+b^(2))^(3)

By using properties of determinants. Show that: (i) |1a a^2 1bb^2 1cc^2|=(a-b)(b-c)(c-a) (ii) |1 1 1a b c a^3b^3c^3|=(a-b)(b-c)(c-a)(a+b+c)

By using properties of determinants.Show that: det[[a^(2)+1,ab,acab,b^(2)+1,bcca,cb,c^(2)+1]]=(1+a^(2)+b^(2)+b^(2))

|[1+a^(2)-b^(2),2ab,-2b],[2ab,1-a^(2)+b^(2),2a],[2b,-2a,1-a^(2)-b^(2)]| =

Show that |{:(1+a^(2)-b^(2),,2ab,,-2b),(2ab,,1-a^(2)+b^(2),,2a),(2b,,-2a,,1-a^(2)-b^(2)):}| = (1+a^(2) +b^(2))^(3)

The value of the determinant |{:(1+ a^(2) - b^(2),2 ab , - 2b),(2ab, 1 - a^(2) + b^(2), 2a),(2b , -2a , 1-a^(2) - b^(2)):}| is equal to

a a+b a+2b 10. Using properties of determinants, show that |[a,a+b,a+2b],[a+2b,a,a+b],[a+b,a+2b,a]|=9b^2(a+b)

Find the value |{:(1+a^(2)-b^(2),2ab,-2b),(2ab,1-a^(2)+b^(2),2a),(2b,-2a,1-a^(2)-b^(2)):}|

If (a+b):(a-b)=1:5 then (a^2-b^2):(a^2+b^2)=

Solve the determinant using properties |[a-b-c,2a,2a],[2b,b-c-a,2b],[2c,2c,c-a-b]| = (a+b+c)^3