The angle which the rough inclined plane makes with the horizontal when the body placed on it just starts sliding down is called .

A cubical block rests on a plane of mu= sqrt(3) . The angle through which the plane be inclined to the horizontal so that the block just slides down will be -

A cubical block rests on a plane of mu= sqrt(3) . The angle through which the plane be inclined to the horizontal so that the block just slides down will be -

Assertion: A body slides down an inclined plane if the angle of friction is more than the angle of the inclined plane with the horizontal. Reason : When the angle of inclination is equal to the angle of friction, the component of weight parallel to the plane is just sufficient to overcome the frictional force.

A body slides down in a time ‘f from rest along a smooth inclined plane making an angle of 45° with the horizontal. When the same body slides down from rest along a rough inclined plane of same length making the same angle, it takes time ‘pt then the coefficient of friction between the body and the rough plane is (p is a constant)

A block of mass m rests on a rough inclined plane. The coefficient of friction between the surface and the block is µ. At what angle of inclination theta of the plane to the horizontal will the block just start to slide down the plane?

A block of mass m rests on a rough inclined plane. The coefficient of friction between the surface and the block is µ. At what angle of inclination theta of the plane to the horizontal will the block just start to slide down the plane?