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If f:NrarrN is given by f(x)={((x+1)/(2)...

If `f:NrarrN` is given by `f(x)={((x+1)/(2), if x " is odd"),((x)/(2),if x " is even"):}` and `g:NrarrN is given by `g(x)=x-(-1)^x`, then `f(g(x))` is (a) one one and onto (b) may one and onto (c) one one and not onto (d) neither one-one onto

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