The time `T` of oscillation of as simple pendulum of length `l` is given by `T=2pi sqrt(l/g)`. The percentage error in `T` corresponding to an error of 2% in the value of `l` is

The time T of of oscillation of a simple pendulum of length l is given by T=2pisqrt(l/g) . Find the percentage error in T, corresponding to an error of 2% in the value of l.

The time period T of oscillation of a simple pendulum of length l is given by T=2pi. sqrt((l)/(g)) . Find the percentage error in T corresponding to 2% in the value of l.

The time T of oscillation of a simple pendulum of length l is given by T=2pi. sqrt((l)/(g)) . Find the percentage error in T corresponding to (i) on increase of 2% in the value of l. (ii) decrease of 2% in the value of l.

The time period T of oscillation of a simple pendulum of length l is given by T=2pi. sqrt((l)/(g)) . Find the percentage error in T corresponding to (i) on increase of 2% in the value of l. (ii) decrease of 2% in the value of l.

The time period 'T' of a simple pendulum of length 'l' is given by T = 2pisqrt(l/g) .Find the percentage error in the value of 'T' if the percentage error in the value of 'l' is 2%.

The time period 'T' of a simple pendulum of length 'l' is given by T = 2pisqrt(l/g) .Find the percentage error in the value of 'T' if the percentage error in the value of 'l' is 2%.

The time t of a complete oscillation of a simple pendulum of length l is given by the equation T=2pisqrt(1/g) where g is constant. What is the percentage error in T when l is increased by 1%?

The time t of a complete oscillation of a simple pendulum of length l is given by the equation T=2pisqrt(1/g) where g is constant. What is the percentage error in T when l is increased by 1%?

The time t of a complete oscillation of a simple pendulum of length l is given by the equation T=2pisqrt(1/g) where g is constant. What is the percentage error in T when l is increased by 1%? Comment the above result.