The pH of 0.1 M `NaHCO_(3)` is (Given `K_(a1)` and `K_(a2)` for `H_(2)CO_(3)` are 6.38 and 10.26 respectively. )

Why is K_(a_2) lt lt K_(a_1) for H_2SO_4 in water?

Find the pH of " 0.1 M NaHCO_(3)" . Use data (K_(1)=4xx10^(-7),K_(2)=4xx10^(-11) for H_(2)CO_(3), log 4=0.6) :

Find the pH of " 0.1 M NaHCO_(3)" . Use data (K_(1)=4xx10^(-7),K_(2)=4xx10^(-11) for H_(2)CO_(3), log 4=0.6) :

A solution contains 0.1M H_2S and 0.3M HCI. If K_a and K_(a2) for H_2 S are 1 xx 10^(-7) and 1.3 xx 10^(-13) respectively, calculate concentration of HS^- and S^- in the mixture.

Why is K_(a_2) << k_(a_1) for H_2SO_4 in water?

Calculate approximate pH of the resultant solution formed by titration of 25 mL of 0.04 M Na_(2)CO_(3) with 50 mL of 0.025 M HCl. [Given : pK_(a1)=6.4 and pK_(a2)=10.3 for H_(2)CO_(3)]