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Determinant of order 3...

Determinant of order 3

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Consider the set A of all determinants of order 3 with entries 0 or 1 only. Let B be the subset of A consisting of all determinants with value 1. Let C be the subset of the set of all determinants with value -1 . Then

Consider the set A of all determinants of order 3 with entries 0 or 1 only . Let B be the subset of A containing of all determinants with value 1. Let C be the subset of the set of all determinants with value - 1. Then

Consider the set A of all determinants of order 3 with entries 0 or 1 only.Let B be the subset of A consisting of all determinants with value 1.Let C be the subset of the set of all determinants with value -1. Then

Consider the set A of all determinants of order 3 with entries 0 or 1 only. Let B be the subset of A consisting of all determinants with value 1. Let C be the subset of the set of all determinants with value -1 . Then

Consider the set A of all determinants of order 3 with entries 0 or 1 only. Let B be the subset of A consisting of all determinants with value 1. Let C be the subset of the set of all determinants with value -1 . Then prove that B equals to C

If the determinant |a+p l+x u+fb+q x+y v+gc+r n+z w+h| splits into exactly K determinants of order 3, each element of which contains only one term, then the values of K is

If the determinant |a+p l+x u+fb+q x+y v+gc+r n+z w+h| splits into exactly K determinants of order 3, each element of which contains only one term, then the values of K is

If the determinant |(x+a,p+u,l+f),(y+b,q+v,m+g),(z+c,r+w,n+h)| splits into exactly k determinants of order 3, each element of which contains onlyone term, then the value of k is 8.

If the determinant |(x+a,p+u,l+f),(y+b,q+v,m+g),(z+c,r+w,n+h)| splits into exactly k determinants of order 3, each element of which contains onlyone term, then the value of k is 8.