The abscissa of the point on the curve `ay^2 = x^3`, the normal at which cuts off equal intercepts from the coordinate axes is

Find the abscissa of the point on the curve x^(3)=ay^(2) , the normal at which cuts off equal intecepts from the coordinate axes.

The abscissa of the point on the curve sqrt(x y)=a+x the tangent at which cuts off equal intercepts from the coordinate axes is -a/(sqrt(2)) (b) a//sqrt(2) (c) -asqrt(2) (d) asqrt(2)

The abscissa of the point on the curve sqrt(x y)=a+x the tangent at which cuts off equal intercepts from the coordinate axes is -a/(sqrt(2)) (b) a//sqrt(2) (c) -asqrt(2) (d) asqrt(2)

The abscissa of the point on the curve sqrt(x y)=a+x the tangent at which cuts off equal intercepts from the coordinate axes is -a/(sqrt(2)) (b) a//sqrt(2) (c) -asqrt(2) (d) asqrt(2)

The abscissa of the point on the curve sqrt(x y)=a+x the tangent at which cuts off equal intercepts from the coordinate axes is -a/(sqrt(2)) (b) a//sqrt(2) (c) -asqrt(2) (d) asqrt(2)

The abscissa of the point on the curve sqrt(x y)=a+x the tangent at which cuts off equal intercepts from the coordinate axes is (b) a//sqrt(2) (c) -asqrt(2) (d) asqrt(2)

The abscissa of the point on the curve sqrt(xy)=a+x the tangent at which cuts off equal intercepts from the coordinate axes is -(a)/(sqrt(2))( b) a/sqrt(2)(c)-a sqrt(2)(d)a sqrt(2)

The abscissa of a point on the curve x y=(a+x)^2, the normal which cuts off numerically equal intercepts from the coordinate axes, is (a) -1/(sqrt(2)) (b) sqrt(2)a (c) a/(sqrt(2)) (d) -sqrt(2)a

The abscissa of a point on the curve x y=(a+x)^2, the normal which cuts off numerically equal intercepts from the coordinate axes, is -1/(sqrt(2)) (b) sqrt(2)a (c) a/(sqrt(2)) (d) -sqrt(2)a