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The angle of which the velocity vector o...

The angle of which the velocity vector of a projectile thrown with a velocity u at an angle `theta` to the horizontal will take with the horizontal after time t of its being thrown up is

A

`theta`

B

`tan^(-1)(theta/t)`

C

`tan^(-1) ((v cos theta)/(v sintheta-"gt"))`

D

`tan^(-1) ((v sintheta-"gt")/(v cos theta))`

Text Solution

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The correct Answer is:
D
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