If A = 1 and B = 0, then in terms of Boolean algebra , `A + bar(B) =` .

Options

A. B
B. `bar(B).B`
C. A
D. `barA`

Answer

To solve the problem step by step, we will use Boolean algebra principles.

### Step-by-Step Solution:

1. **Identify the Given Values**:
- We are given that \( A = 1 \) and \( B = 0 \).

2. **Determine \( B \) Bar**:
- In Boolean algebra, the bar (or NOT operation) inverts the value.
- Since \( B = 0 \), we calculate \( B' \) (or \( \bar{B} \)):
\[ B' = \bar{B} = 1 \quad (\text{because NOT of 0 is 1}) \]

3. **Substitute Values into the Expression**:
- Now we substitute \( A \) and \( B' \) into the expression \( A + \bar{B} \):
\[ A + \bar{B} = 1 + 1 \]

4. **Apply the Boolean Addition Rule**:
- In Boolean algebra, the addition operation follows the rule:
- \( 1 + 1 = 1 \)
- Therefore:
\[ A + \bar{B} = 1 \]

5. **Final Result**:
- The value of \( A + \bar{B} \) is:
\[ A + \bar{B} = 1 \]

### Conclusion:
The final answer is \( 1 \).

---