An object of specific gravity `rho` is hung from a thin steel wire. The fundamental frequency for transverse standing waves in wire is `300 Hz`. The object is immersed in water so that one half of its volume is submerged. The new fundamental frequency in `Hz` is

Options

A. `300 ((2rho-1)/(2rho))^(1/2)`
B. `300 ((2rho)/(2rho-1))^(1/2)`
C. `300 ((2rho)/(2rho-1))`
D. `300 ((2rho-1)/(2rho))`

Answer

A