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An automobile travelling at 50 km h^(-1)...

An automobile travelling at 50 km `h^(-1)` ,can be stopped at a distance of 40 cm by applying brakes. If the same automobile is travelling at `90 km h^(-1)` ,all others conditions remaining the same and assuming no skidding, the minimum stopping distance in cm is

A

72

B

92.5

C

102.6

D

129.6

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The correct Answer is:
To solve the problem step by step, we will use the equations of motion to find the stopping distance of the automobile when traveling at different speeds. ### Step 1: Convert the speeds from km/h to m/s We need to convert the speeds from kilometers per hour (km/h) to meters per second (m/s) using the conversion factor \( \frac{5}{18} \). - For \( U_1 = 50 \, \text{km/h} \): \[ U_1 = 50 \times \frac{5}{18} = \frac{250}{18} \approx 13.89 \, \text{m/s} \] - For \( U_2 = 90 \, \text{km/h} \): \[ U_2 = 90 \times \frac{5}{18} = \frac{450}{18} = 25 \, \text{m/s} \] ### Step 2: Use the equation of motion to find acceleration We know from the problem that the stopping distance \( S_1 \) at speed \( U_1 \) is 40 cm (which is 0.4 m). We will use the third equation of motion: \[ V^2 = U^2 + 2AS \] where \( V = 0 \) (final velocity), \( U = U_1 \), \( A \) is the acceleration (deceleration in this case), and \( S = S_1 \). Rearranging the equation to find \( A \): \[ 0 = U_1^2 + 2AS_1 \implies A = -\frac{U_1^2}{2S_1} \] Substituting the values: \[ A = -\frac{(13.89)^2}{2 \times 0.4} = -\frac{193.6121}{0.8} \approx -242.01 \, \text{m/s}^2 \] ### Step 3: Calculate the stopping distance at \( U_2 \) Now we will find the stopping distance \( S_2 \) when the automobile is traveling at \( U_2 = 25 \, \text{m/s} \). Again using the equation of motion: \[ 0 = U_2^2 + 2AS_2 \implies S_2 = -\frac{U_2^2}{2A} \] Substituting the values: \[ S_2 = -\frac{(25)^2}{2 \times -242.01} = \frac{625}{484.02} \approx 1.29 \, \text{m} \] ### Step 4: Convert \( S_2 \) to centimeters Since we need the answer in centimeters: \[ S_2 = 1.29 \, \text{m} \times 100 = 129 \, \text{cm} \] ### Final Answer The minimum stopping distance when the automobile is traveling at \( 90 \, \text{km/h} \) is approximately **129 cm**. ---
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