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Radii of two conducting circular loops a...

Radii of two conducting circular loops are b and a respectively, where `bgtgta` Centres of both loops coincide but planes of both loops are perpendicular each other. The value of mutual inductance for these loops

A

`(mu_0pib^2)/(2a)`

B

Zero

C

`(mu_0piab)/(2(a+b))`

D

`(mu_0pia^2)/(2b)`

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The correct Answer is:
To find the mutual inductance between two conducting circular loops with radii \( b \) and \( a \) (where \( b \gg a \)), and with their planes perpendicular to each other, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Configuration**: - We have two circular loops: one with radius \( b \) and the other with radius \( a \). - The centers of both loops coincide, but their planes are perpendicular to each other. 2. **Magnetic Field Due to the Larger Loop**: - The magnetic field \( B \) at the center of the larger loop (radius \( b \)) due to a current \( I \) flowing through it is given by the formula: \[ B = \frac{\mu_0 I}{2b} \] where \( \mu_0 \) is the permeability of free space. 3. **Calculating the Magnetic Flux through the Smaller Loop**: - The area vector of the smaller loop (radius \( a \)) is perpendicular to its plane. Since the planes of the loops are perpendicular, the angle \( \theta \) between the magnetic field \( B \) and the area vector \( A \) of the smaller loop is \( 90^\circ \). - The magnetic flux \( \Phi \) through the smaller loop is given by: \[ \Phi = B \cdot A = B \cdot A \cos(\theta) \] - Since \( \theta = 90^\circ \), we have: \[ \Phi = B \cdot A \cos(90^\circ) = 0 \] 4. **Mutual Inductance Calculation**: - The mutual inductance \( M \) is defined as the ratio of the magnetic flux \( \Phi \) through one loop due to the current in the other loop: \[ M = \frac{\Phi}{I} \] - Since we found that \( \Phi = 0 \), we can conclude: \[ M = \frac{0}{I} = 0 \] ### Conclusion: The mutual inductance \( M \) between the two loops is zero because the magnetic field lines from the larger loop do not pass through the smaller loop due to the perpendicular orientation of their planes.
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