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Electrons with de-Broglie wavelength lam...

Electrons with de-Broglie wavelength `lambda` fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray is

A

`lamda_0 = (2mclamda^2)/h`

B

`lamda_0 = (2h)/(mc)`

C

`lamda_0=(2m^2c^2lamda^2)/h^2`

D

`lamda_0=lamda`

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The correct Answer is:
A
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