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The wavelength of de - Broglie wave is 2...

The wavelength of de - Broglie wave is `2 mu m` , then its momentum is `( h = 6.63 xx 10^(-34 ) J-s)`

A

`3.315 xx10^(-28) kg ms ^(-1)`

B

`1.66 xx10^(-28) kg ms ^(-1)`

C

`4.97 xx10^(-28) kg ms ^(-1)`

D

`9.9 xx10^(-28) kg ms ^(-1)`

Text Solution

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The correct Answer is:
A
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The de-Broglie wavelength of an electron is 600 nm . The velocity of the electron is: (h = 6.6 xx 10^(-34) J "sec", m = 9.0 xx 10^(-31) kg)

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