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A current of 2.34 A flows in resistance ...

A current of 2.34 A flows in resistance of `11. 111111Omega` The potential difference across the given resistance with due regard for the significant figure is

A

26.000 A

B

26.00 A

C

26.0 V

D

26 V

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The correct Answer is:
To solve the problem of finding the potential difference across a resistance when a current flows through it, we will use Ohm's Law, which states: \[ V = I \times R \] Where: - \( V \) is the potential difference (voltage), - \( I \) is the current (in amperes), - \( R \) is the resistance (in ohms). ### Step-by-Step Solution: 1. **Identify the Given Values**: - Current \( I = 2.34 \, \text{A} \) - Resistance \( R = 11.111111 \, \Omega \) 2. **Apply Ohm's Law**: - Substitute the values into the formula: \[ V = I \times R = 2.34 \, \text{A} \times 11.111111 \, \Omega \] 3. **Perform the Multiplication**: - Calculate the product: \[ V = 2.34 \times 11.111111 = 25.99999994 \, \text{V} \] 4. **Round to the Correct Number of Significant Figures**: - The current \( 2.34 \) has three significant figures. - The resistance \( 11.111111 \) has eight significant figures. - The result should be rounded to three significant figures (the lesser number of significant figures). - Thus, \( 25.99999994 \) rounded to three significant figures is \( 26.0 \, \text{V} \). 5. **Final Answer**: - The potential difference across the resistance is: \[ V = 26.0 \, \text{V} \]
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