The moment of inertia of a rod about an axis through its centre and perpendicular to it is `(1)/(12) ML^(2)` (Where M is the mass and L, the length of the rod). The rod is bent in the middle so that the two halves make an angle of `60^(@)` The moment of inertia of the bent rod about the same axis would be ;

Options

A. `(ML^2)/48`
B. `(ML^2)/12`
C. `(ML^2)/24`
D. `(ML^2)/(8sqrt3)`

Answer

B