The quantity of a charge that will be transferred by a current flow of 20 A over 1 h 30 min period is

Options

A. `10.8xx10^3C`
B. `10.8xx10^4C`
C. `5.4xx10^3C`
D. `1.8xx10^4C`

Answer

To find the quantity of charge transferred by a current flow of 20 A over a period of 1 hour and 30 minutes, we can follow these steps:

### Step 1: Convert the time from hours and minutes to seconds
1 hour = 60 minutes, so:
1 hour and 30 minutes = 60 minutes + 30 minutes = 90 minutes.

Now, convert minutes to seconds:
\[ 90 \text{ minutes} = 90 \times 60 \text{ seconds} = 5400 \text{ seconds} \]

### Step 2: Use the formula for charge
The relationship between charge (Q), current (I), and time (t) is given by the formula:
\[ Q = I \times t \]
where:
- \( Q \) is the charge in Coulombs,
- \( I \) is the current in Amperes,
- \( t \) is the time in seconds.

### Step 3: Substitute the values into the formula
Given:
- Current \( I = 20 \text{ A} \)
- Time \( t = 5400 \text{ seconds} \)

Now substitute these values into the formula:
\[ Q = 20 \text{ A} \times 5400 \text{ s} \]

### Step 4: Calculate the charge
Now, perform the multiplication:
\[ Q = 20 \times 5400 = 108000 \text{ Coulombs} \]

### Step 5: Express the charge in scientific notation
To express \( 108000 \) in scientific notation:
\[ 108000 = 1.08 \times 10^5 \text{ Coulombs} \]

### Final Answer
The quantity of charge transferred is:
\[ Q = 1.08 \times 10^5 \text{ Coulombs} \]

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