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A block of mass m is placed on a smooth wedge of inclination `theta`. The whole system is accelerated horizontally, so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be

A

`(mg)/(costheta)`

B

`mg cos theta`

C

`mg sin theta`

D

`(mg)/(sin theta)`

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The correct Answer is:
A
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