If the binding energy per nucleon in .(3...

If the binding energy per nucleon in `._(3)Li^(7)` and `._(2)He^(4)` nuclei are respectively `5.60` MeV and `7.06` MeV, then the ebergy of proton in the reaction `._(3)Li^(7) +p rarr 2 ._(2)He^(4)` is

19.6 MeV

2.4 MeV

8.4 MeV

17.3 MeV

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If the binding energy per nucleon in ._(3)Li^(7) and ._(2)He^(4) nuclei are respectively 5.60 MeV and 7.06 MeV, then the energy of proton in the reaction ._(3)Li^(7) +p rarr 2 ._(2)He^(4) is

If the binding energy per nucleon in L i^7 and He^4 nuclei are respectively 5.60 MeV and 7.06 MeV . Then energy of reaction L i^7 + p rarr 2_2 He^4 is.

If the binding energy per nucleon in ._(3)^(7)Li and ._(2)^(4)He nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction p+._(3)^(7)Lirarr2._(2)^(4)He energy of proton must be:

If the binding energy per nucleon in _(3)^(7) Li and _(2)^(4)He nuclei are 5.60 MeV and 7.06MeV respectively then in the reaction P +_(3)^(7) Li rarr 2 _(2)^(4) He energy of proton mnust be

The binding energy per nucleon of ._(3)^(7) Li and ._(2)^(4)He nuclei are 5.60 MeV and 7.06 MeV, respectively. In the nuclear reaction ._(3)^(7)Li+._(1)^(1)H rarr ._(2)^(4)He+._(2)^(4)He+Q , the value of energy Q released is

The binding energy per nucleon for ._(3)Li^(7) will be, if the mass of ._(3)Li^(7) is 7.0163 a.m.u.

The binding energy per nucleon for ""_(1)H^(2) and ""_(2)He^(4) are 1.1 MeV and 7.1 MeV respectively. The energy released when two ""_(1)H^(2) to form ""_(2)He^(4) is ………….. MeV.

Binding energy per nucleus of ._(1)^(2)H and ._(2)^(4)He are 1.1 MeV and 7 MeV respectively. Calculate the amount of energy released in the following process: ._(1)^(2)H + ._(1)^(2)H to ._(2)^(4)He

Calculate the energy of the reaction , Li^(7) + p to 2 _(2)He^(4) If the binding energy per nucleon in Li^(7) and He^(4) nuclei are 5.60 MeV and 7.06 MeV , respectively .

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