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A particle is projected with a velocity ...

A particle is projected with a velocity `v` so that its range on a horizontal plane is twice the greatest height attained. If `g` is acceleration due to gravity, then its range is

A

`(4v^2)/(5g)`

B

`(4g)/(5v^2)`

C

`(4v^2)/(5g^2)`

D

`(4v)/(5g^2)`

Text Solution

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The correct Answer is:
A
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