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Power radiated by a black body is P0 and...

Power radiated by a black body is `P_0` and the wavelength corresponding to maximum energy is around `lamda_0`, On changing the temperature of the black body, it was observed that the power radiated becames `(256)/(81)P_0`. The shift in wavelength corresponding to the maximum energy will be

A

`+lamda_0/4`

B

`+lamda_0/2`

C

`-lamda_0/4`

D

`-lamda_0/2`

Text Solution

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The correct Answer is:
C
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