The angle of dip at a certain place on earth is `60^@` and the magnitude of the earth's horizontal component of the magnetic field is 0.26 G . The magnetic field at the place on earth is

Options

A. 0.13 G
B. 0.26 G
C. 0.52 G
D. 0.65 G

Answer

To find the magnetic field at a certain place on Earth given the angle of dip and the horizontal component of the magnetic field, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Angle of dip (θ) = 60°
- Horizontal component of the magnetic field (Vh) = 0.26 G

2. **Understand the Relationship:**
The relationship between the total magnetic field (Ve), the horizontal component (Vh), and the angle of dip (θ) is given by:
\[ V_e = \frac{V_h}{\cos \theta} \]

3. **Calculate Cosine of the Angle:**
For θ = 60°:
\[ \cos 60° = \frac{1}{2} \]

4. **Substitute the Values:**
Substitute the values into the equation:
\[ V_e = \frac{0.26 \, \text{G}}{\cos 60°} = \frac{0.26 \, \text{G}}{\frac{1}{2}} = 0.26 \times 2 \, \text{G} \]

5. **Perform the Calculation:**
\[ V_e = 0.52 \, \text{G} \]

6. **Conclusion:**
The magnetic field at the place on Earth is 0.52 G.

### Final Answer:
The magnetic field at the place on Earth is **0.52 G**.

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