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Force between two identical charges plac...

Force between two identical charges placed at a distance of `r` in vacuum is `F`.Now a slab of dielectric constant 4 is inserted between these two charges . If the thickness of the slab is `r//2`, then the force between the charges will becomes

A

`3/5F`

B

`4/9F`

C

`F/4`

D

`F/2`

Text Solution

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The correct Answer is:
B
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