A paramagnetic substance of susceptibility `3 xx10^(-4)` is placed in a magnetic field of `3xx 10^(-4)A m^(-1)`. . Then , the intensity of magnetisation in units of A `m^(-1)` is

Options

A. `9xx10^(-8)`
B. `1xx10^(-4)`
C. `1xx10^(-3)`
D. `9xx10^(-10)`

Answer

To find the intensity of magnetization (I) of a paramagnetic substance given its magnetic susceptibility (χ) and the magnetic field strength (H), we can use the relationship:

\[ \chi = \frac{I}{H} \]

Where:
- \( \chi \) is the magnetic susceptibility,
- \( I \) is the intensity of magnetization,
- \( H \) is the magnetic field strength.

### Step 1: Identify the given values
- Magnetic susceptibility, \( \chi = 3 \times 10^{-4} \)
- Magnetic field strength, \( H = 3 \times 10^{-4} \, \text{A/m} \)

### Step 2: Rearrange the formula to solve for I
From the formula \( \chi = \frac{I}{H} \), we can rearrange it to find \( I \):

\[ I = \chi \times H \]

### Step 3: Substitute the values into the equation
Now, substitute the known values into the equation:

\[ I = (3 \times 10^{-4}) \times (3 \times 10^{-4}) \]

### Step 4: Perform the multiplication
Now calculate the product:

\[ I = 9 \times 10^{-8} \, \text{A/m} \]

### Final Answer
The intensity of magnetization \( I \) is:

\[ I = 9 \times 10^{-8} \, \text{A/m} \]