For the arrangement in the Figure, the particle `M_(1)` attached to one end of string which moves on a horizantal table in a circle of radius `l/2` (where `l` is the length of the string) with constant angular speed `omega`. The other end of the string attached to to mass `M_(2)` which rest on a vertical rod. When the rod collapse, the acceleration of mass `M_(2)` at that instant

Options

A. `g`
B. `(omega^(2)l)/(2)`
C. `(2M_(2)g-M_(1)lomega^(2))/(2(M_(1)+M_(2)))`
D. `(M_(2)g+M_(1)lomega^(2))/(M_(1)+M_(2))`

Answer

C