The areas of the two similar triangles a...

The areas of the two similar triangles are in the ratio of the square of the corresponding medians.

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BD=DC=1/2BC
QS=SR=1/2QR
`(BD)/(QS)=(DC)/(SR)=(BC)/(QR)`
-(1) `/_ABC`~`/_PQR`(AAA)
`(AB)/(PQ)=(BC)/(QR)=(CA)/(RP)`
`angleB=angleQ`
`/_ABC`~`/_PQS`

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