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In a Coolidge tube, the potential differ...

In a Coolidge tube, the potential difference used to accelerate the electrons is increased from 24. 8 kV to 49.6 kV . As a result, the difference between the wavelength of `K_(alpha)` -line and minimum wavelength becomes two times. The initial wavelength of the `K_(alpha)` line is [Take `(hc)/(e) = 12 .4 kV Å`]

A

`0.75Å`

B

`1.50Å`

C

`0.25Å`

D

`0.50Å`

Text Solution

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The correct Answer is:
A
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In a Coolidge tube, the potential difference used to accelerate the electrons is increased from 12.4 kV to 24.8 kV . As a result, the difference between the wavelengths of K_(alpha) -line and minimum wavelength becomes thrice. The wavelength of the K_(alpha) line is 0.25xxKA^(@) . Find the value of K . (hc)/(e)=(12.4 KVA^(@))

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Knowledge Check

  • In X-ray tube , when the accelerating voltage V is halved, the difference between the wavelength of K_(alpha) line and minimum wavelength of continuous X-ray spectrum

    A
    remain constant
    B
    because more than two times
    C
    because half
    D
    because less than two times

  • A potential difference of 15 KV is applied to accelerate the electron in an electron microscope. The de broglie wavelength of the electron waves is

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  • The potential difference between the cathode. And the target electrod in a coolidge tube is 24.75 kV. The minimum wavelength of the emitted X-rays is

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