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Light of wavelength 600 nm is incident n...

Light of wavelength 600 nm is incident normally on a slit of width 0.2 mm. The angular width of central maxima in the diffraction pattern is

A

` 6 xx 10^(-3) rad`

B

` 4 xx 10^(-3) rad`

C

` 2.4 xx 10^(-3) rad`

D

` 4.5 xx 10^(-3) rad`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • Light of wavelength 5000Å is incident over a slit of width 1 mu m . The angular width of central maxima will be

    A
    `30^(@)`
    B
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  • When wave of wavelength 0.2cm is made incident normally ona slit of width 0.004m then the semui-angular width of central maximum of diffraction patten will be-

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    B
    `30^(@)`
    C
    `90^(@)`
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    Light of wavelength 600 nm is incident normally on a slit of width 3 mm . Calculate linear width of central maximum on a screen kept 3 m away from the slit.

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