A hydrogen like atom with atomic number ...

A hydrogen like atom with atomic number Z is in an excited state of quantum number 2n. It can emit a maximum energy photon of 204 eV. If it makes a transition to quantum state n, a photon of energy 40.8 eV is emitted. Find n, Z and the ground state energy (in eV) of this atom. Also calculate the minimum energy (in eV) that can be emitted by this atom during de-excitation. Ground state energy of hydrogen atom is – 13. 6 eV.

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A hydrogen like atom number Z is in an excited state of quantum number 2n. It can emit a maximum energy photon of 204 eV. If it makes a transition ot quantum state n, a photon of energy 40.8 eV is emitted. Find n, Z and the ground state energy (in eV) of this atom. Also calculate the minimum energy of hydrogen atom is -13.6 ev.

A hydrogen - like atom of atomic number Z is in an excited state of quantion number 2 n it can emit a maximum energy photon of energy 40.8 eV is emitted find n , Z and the ground state energy (in eV) for this atom . Also calculate the minimum energy (in eV) that can be emitted by this atom during de- exclation , Ground state energy of hydrogen atom is - 13.6 eV

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