A particle is revolving in a circular path as shown in figure in the horizontal plane such that the angular velocity of the particle about the point O is constant and is equal to `1 rad//s`. Distance of the particle from O is given by`R=R_(0)-betat` where `R_(0)`and `beta` are constant. The speed of the particle as a function of time is:

Options

A. `sqrt(beta^(2)+1)`
B. `(R_(0)-betat)`
C. `sqrt(beta^(2)+(R_(0)-betat)^(2))`
D. `beta`

Answer

C