Geometrical isomerism is show by

Options

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B.
C.
D.

Answer

To solve the question regarding geometrical isomerism, we need to analyze the given compounds and determine which one exhibits this type of isomerism. Geometrical isomerism, also known as cis-trans isomerism, occurs in compounds with restricted rotation around a double bond or a ring structure, where different substituents can lead to different spatial arrangements.

### Step-by-Step Solution:

1. **Identify the Compounds**:
The question provides four compounds. We need to analyze each one to see if it can exhibit geometrical isomerism.

2. **Analyze Each Compound**:
- **Compound 1**: Cl, Br, CH3, CH3
- This compound has two identical CH3 groups. Since there are identical groups on one side of the double bond, it cannot exhibit geometrical isomerism.

- **Compound 2**: C=C with Cl, Cl, H, CH3
- This compound has two different groups (Cl and CH3) attached to one of the carbons and two Cl atoms on the other carbon. The presence of the CH3 and Cl allows for cis (same side) and trans (opposite side) configurations, indicating that this compound can exhibit geometrical isomerism.

- **Compound 3**: C=C with H, H, CH3, CH3
- Similar to Compound 1, this compound has two identical groups (H) on one side, which prevents it from showing geometrical isomerism.

- **Compound 4**: C=C with F, F, H, CH3
- This compound has two identical fluorine atoms on one side, which also prevents it from showing geometrical isomerism.

3. **Conclusion**:
Based on the analysis, only Compound 2 (C=C with Cl, Cl, H, CH3) can exhibit geometrical isomerism due to the presence of different substituents on one side of the double bond.

### Final Answer:
The compound that shows geometrical isomerism is **Compound 2**.