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The reaction of t - butyl chloride and s...

The reaction of t - butyl chloride and sodium ethoxide gives mainly

A

t - butyl ethyl ether

B

2,2 - dimethylbutane

C

2 - methylprop -1 - ene

D

isopropyl n- propyl ether

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The correct Answer is:
To solve the question regarding the reaction of t-butyl chloride with sodium ethoxide, we will follow these steps: ### Step 1: Identify the Reactants The reactants in this reaction are t-butyl chloride (C4H9Cl) and sodium ethoxide (C2H5ONa). ### Step 2: Understand the Structure of t-Butyl Chloride t-Butyl chloride is a tertiary alkyl halide, which means it has three alkyl groups attached to the carbon that is bonded to the chlorine atom. The structure can be represented as follows: ``` CH3 | CH3-C-Cl | CH3 ``` ### Step 3: Recognize the Role of Sodium Ethoxide Sodium ethoxide is a strong base and a good nucleophile. In this reaction, it will primarily act as a strong base due to the steric hindrance present in the t-butyl chloride. ### Step 4: Determine the Type of Reaction Given that t-butyl chloride is a tertiary alkyl halide, the reaction with sodium ethoxide will favor an elimination reaction (E2) rather than a substitution reaction (SN2). This is because SN2 reactions are not favorable for tertiary substrates due to steric hindrance. ### Step 5: Mechanism of E2 Elimination In the E2 mechanism: - The ethoxide ion (C2H5O-) will abstract a beta hydrogen from the t-butyl chloride. - The bond between the beta hydrogen and its carbon will break, leading to the formation of a double bond between the alpha carbon and the beta carbon. - The chlorine atom will be eliminated as a chloride ion. ### Step 6: Identify the Product The beta hydrogen that is abstracted is from one of the methyl groups adjacent to the t-butyl group. The resulting product after elimination will be propene (C3H6), specifically 2-methylpropene, which can be represented as: ``` CH3 | CH3-C=CH2 ``` ### Step 7: Name the Product The product formed is 2-methylpropene, which is the major product of the reaction. ### Conclusion The major product of the reaction between t-butyl chloride and sodium ethoxide is **2-methylpropene**. ---
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