Sodium reacts with alcohol as given below `2Na+ 2ROH rarrH_2+2[Na^(+) bar(O)R]` place the types of alcohol into decreasing order of reactivity towards Na

Options

A. `1^@ gt 2^@ gt 3^@`
B. `1^@ gt 3^@ gt 2^@`
C. `2^@ gt 3^@ gt 1^@`
D. `3^@ gt 2^@ gt 1^@`

Answer

To determine the decreasing order of reactivity of different types of alcohols towards sodium (Na), we need to consider the acidic nature of the alcohols. The more acidic an alcohol is, the more reactive it will be with sodium.

### Step-by-Step Solution:

1. **Understand the Reaction**:
The reaction given is:
\[ 2Na + 2ROH \rightarrow H_2 + 2[Na^+ \bar{(O)R}] \]
Here, \(ROH\) represents alcohol, where \(R\) is an alkyl group.

2. **Identify the Types of Alcohol**:
The types of alcohols we will consider are:
- Primary (1°) Alcohols
- Secondary (2°) Alcohols
- Tertiary (3°) Alcohols
- Methanol (CH₃OH)

3. **Determine Acidity**:
The reactivity of alcohols with sodium is influenced by their acidic nature. The order of acidity (and thus reactivity towards sodium) is as follows:
- Methanol (CH₃OH) is more acidic than primary alcohols.
- Primary alcohols are more acidic than secondary alcohols.
- Secondary alcohols are more acidic than tertiary alcohols.

4. **Establish the Order of Reactivity**:
Based on the acidity, we can establish the following order of reactivity towards sodium:
- Methanol (CH₃OH) > Primary Alcohols (1°) > Secondary Alcohols (2°) > Tertiary Alcohols (3°)

5. **Final Answer**:
Therefore, the decreasing order of reactivity of alcohols towards sodium is:
\[ \text{CH}_3\text{OH} > \text{1° Alcohol} > \text{2° Alcohol} > \text{3° Alcohol} \]